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-0.5x^2+2x+22.5=0
a = -0.5; b = 2; c = +22.5;
Δ = b2-4ac
Δ = 22-4·(-0.5)·22.5
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-7}{2*-0.5}=\frac{-9}{-1} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+7}{2*-0.5}=\frac{5}{-1} =-5 $
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